Satellite photos show how pitiful ice cover is in the Arctic right now

Mark Kaufman
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    Clyde
    "Specifically, as more ice melts, there's less bright ice cover to reflect the sun. Instead, the dark ocean absorbs more heat, warming the region even more."

    This exaggeration gets repeated again and again without any quantitative justification for it! The ice looks bright because light is reflected diffusely in all directions. The ocean looks dark, as any fisherman is quite aware, because all the sunlight is reflected specularly away from the sun and one has to be facing the sun to see the sheaf of light.
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      Robert Paulson
      The Bering sea isn't the north pole you amazingly stupid idiot.
      Imageswansfeather
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      Clyde
      @Robert Paulson Speaking of dumb, by definition, the sun's rays are parallel to the geographic North Pole at the equinoxes! The oceans are illuminated by the sun at glancing angles EVERY sunrise and sunset. Take a look at this picture:
      https://weatherpictureoftheday.com/2019/03/27/sunset-at-seymour-beach/

      This is what I mean about someone who thinks he knows something (everything?) when he knows almost nothing. Unfortunately, you think that you are smarter and better educated than what there is any evidence for.
      Seymour Beach, Ontario, Canada Photo Credit: Donna Rusnak Click for larger image.
      Seymour Beach, Ontario, Canada Photo Credit: Donna Rusnak Click for larger image.
      weatherpictureoftheday.com
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      Robert Paulson
      My god you are dumb, Clyde, oceans are neither smooth surfaces nor hit by sunlight at glancing angles. None of your links support anything you have posted. Open ocean absorbs heat from the sun, it's basic science, that has been explained to you numerous times.
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      Clyde
      @Robert Paulson You are again demonstrating your poor understanding of physics. Actually, for very large angles of incidence, the specularly reflected light from ANY object approaches the spectral distribution of the source. At glancing angles (90 deg) the spectral distribution is identical to the source. That is, the object appears white, with 100% reflectance for all wavelengths! You really are out of your league!

      There is nothing more pathetic than someone who believes he understands something, when in fact he only has an inkling of the complexity of the phenomenon.

      What is with this 'Royal We?' Are you a new incarnation of the PC, MGC, Rich, Quick alter-egos?
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      Clyde
      @Robert Paulson I don't have to memorize it because I already knew it! Thank you for demonstrating that you can cut and paste quotes. Unless you can manipulate Fresnel's equations, you are playing in the wrong sand box.

      https://www.brown.edu/research/labs/mittleman/sites/brown.edu.research.labs.mittleman/files/uploads/lecture13_0.pdf
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      Robert Paulson
      Only white objects reflect all wavelengths of light, as we have explained to you already. Does the ocean look white to you?
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      Clyde
      @Robert Paulson Would you drink black water?
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      Robert Paulson
      When light hits a surface, there are three possible outcomes. Light may be absorbed by the material, light may be transmitted through the surface, or light may be reflected. Materials often show some mix of these behaviors, with the proportion of light that goes to each depending on the properties of the material, the wavelength of the light, and the angle of incidence.

      Memorize that bit of science as well.
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      Robert Paulson
      A black object absorbs all wavelengths of light and converts them into heat, so the object gets warm. A white object reflects all wavelengths of light, so the light is not converted into heat and the temperature of the object does not increase.

      Go ahead and memorize that bit of science, Clyde.
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      Clyde
      @Robert Paulson "... you aren't going to learn what you don't want to know." Look in a mirror!